Question

For the following system of equations what is the x-value?
-x+2y=6
6y=x+18
A.-18
B.0
C.-6
D.3

Answer 1

-x+2y=6
+x +x
2y=6+x
divide both sides by 2
y=(1/2)x+3
now plug it in for y in the other equation
6((1/2)x+3)=x+18
3x+18=x+18
-18 -18
3x=x
-x -x
2x=0
divide each side by 2
x=0

Answer 2

Thank you so much!! @sudukogirl13

Answer 3

ur welcome

Answer 4

1. Isolate one of the variables into one of the equations:

So you have:
-x + 2 y= 6
x + 18 = 6y

Let's start with x + 18 = 6y.
\[x + 18 = 6y\]\[6y-18=x\]So now we know what x equals. Well, not exactly, but enough to know how to solve for y:

2. Substitute the expression for the isolated variable into the other equation and solve for the other variable.
So the other equation is:\[-x+2y=6\]\[-(6y-18)+2y=6\]See what I did there? Mmhmm.


Oh, I was doing it the hard way and sudoko girl got it. T.T

Answer 5

Well thank you to you to !;)