Derive the equation of the parabola with a focus at (4, -7) and a directrix of y = -15. Put the equation in standard form
a. f(x) = 1/16 x2 - 8x + 11 b. f(x) = 1/16 x2 - 8x - 10 d. f(x) = 1/16 x2 - 1/2 x - 10
C was wrong
well you need to find the vertex. but before that you need to find the focal length the distance between the directrix and focus is equal to 2 times the focal length. so what do you think the focal length would be..?
I'm totally lost! The practice problems don't make sense at all:(
And in the lesson it didn't say anything about needing the vertex or focal length I don't think
ok... |dw:1385058491849:dw| the vertex in the line x = 4 and located half way between y = -7 and y = -15 the total distance between y = -7( the focus) and y = -15( the directrix) is a length which is double the focal length
Join our real-time social learning platform and learn together with your friends!