Question

Help!!!!
Which of the following is the slope between the points (-1, -5) and (7, -3)?

A. 4

B. 1/4

C. -1/4

D. -4

Answer 1

Given two points (x1, y1) and (x2, y2),
their slope m can be found from: m = (y2 - y1) / (x2 - x1)

Answer 2

so it would be 4

Answer 3

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&(-1\quad ,&5)\quad &(7\quad ,&-3)
\end{array}
\\\quad \\

slope = m= \cfrac{rise}{run} \implies \cfrac{y_2-y_1}{x_2-x_1}\)

Answer 4

So -4

Answer 5

hmm well.. try this one instead \(\bf slope = m= \cfrac{rise}{run} \implies \cfrac{y_2-y_1}{x_2-x_1}\implies \cfrac{(-3)-(-1)}{(7)-(-1)}\implies \cfrac{-3+1}{7+1}\)

Answer 6

hmmm hold one... that needs some fixing

Answer 7

\(\bf slope = m= \cfrac{rise}{run} \implies \cfrac{y_2-y_1}{x_2-x_1}\implies \cfrac{(-3)-(5)}{(7)-(-1)}\implies \cfrac{-3-5}{7+1}\)

Answer 8

notice your "x" and "y" for each point \(\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&(-1\quad ,&5)\quad &(7\quad ,&-3)
\end{array}\)

Answer 9

0.25x + -4.75

Answer 10

hmnm ohh .. .smokes... is -5.... thought it was ... 5 my bad

Answer 11

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&(-1\quad ,&-5)\quad &(7\quad ,&-3)
\end{array}
\\\quad \\

slope = m= \cfrac{rise}{run} \implies \cfrac{y_2-y_1}{x_2-x_1}\implies \cfrac{(-3)-(-5)}{(7)-(-1)}\implies \cfrac{-3+5}{7+1}\)

Answer 12

0.25

Answer 13

so its 1/4

Answer 14

yeap