Question

Use the 1-1 property of the exponential function to solve the given equation.

a. 3^-x=27

This is what I worked out.

log3(3^-x)=log3(27)

-x=log(27)/log3

-x=3


Am I on the right track or no?

Answer 1

yes

Answer 2

-x = 3, thus x = -3

Answer 3

Thank you!!

Answer 4

\(\bf 3^{-x}=27\implies \cfrac{1}{3^x}=27\implies \cfrac{1}{27}=3^x\quad 27=3^3\quad thus\\ \quad \\
\cfrac{1}{3^3}=3^x\implies 3^{-3}=3^x\)