Question

The force in Newtons on a particle directed along the x-axis is given by F(x)=exp(−(x/2)+6) for x≥0 where x is in meters. The particle is constrained to move along the x-axis. Find the work done in Joules on the particle, W, in moving it from x=0 to x=1 using the fact that F=dW/dx. For your reference, 1 Joule = 1 Newton × 1 meter.

Answer 1

so what is the general expression for work done?

Answer 2

\[Work Done (W) = \int\limits_{0}^{1} e ^{-x/2 + 6} dx\]
W = 317.4737224570294 Joule

Answer 3

thx!!!!!