A gas has a volume of 590 mL at a temperature of –55.0 C. What volume will the gas occupy at 30.0 C?

Question

aaronq · Answer

use: $\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$  (this is charles's law)

ps. the temperature has to be in Kelvin

anonymous · Answer

Someone told me Since V1T1 = V2T2 (590mL)(-550C) divided by (30 0C) = 1081,67 mL but I don't know how to get or convert the answer to Kelvin units...

aaronq · Answer

to convert to K from celsius just add 273.15 .. so -55 celsius to kelvin

273 + (-55)= 218 K

anonymous · Answer

Oooh.. Is that the final product?

aaronq · Answer

that would be one of the temperatures given in Kelvin, but it's not the answer. you'd still have to convert the the other temp and solve for the new volume

anonymous · Answer

Oh gosh... how would I do that?

aaronq · Answer

to convert from celsius to kelvin simply add 273 to the temperature.

e.g. $5^oC $ to kelvin.. 5 + 273  = 278 K

use the equation i wrote above (in my first post) to solve for the new volume

anonymous · Answer

590/218 = V2/303
 V2 = 590 (303/218) = 820 ml

aaronq · Answer

thats right $\checkmark$

jtfan2000 · Answer

(590mL)(-55C) divided by (30C) = 1081.67mL