Question

=

Answer 1

@skullpatrol

Answer 2

f(x)=x

Answer 3

One is line function. However three is a absolute value function so you may be inclined to justify it as a line however at x = o the function is acute and therefore is probably not considered a line. IxI does fail the test for a linear function I.E. it must satisfy f(ax+y)=af(x)+f(y) which it does not so its not a linear function.

Hope this helps :)

Answer 4

don't you get it?

Answer 5

@OOOPS
Don't I get what?

Answer 6

I didn't see you replied or said anything to the helpers. Just make sure whether you get it or not or need more explanation.

Answer 7

I'm sorry. I was waiting for some responses, and moved on to do other things. And no, I'm still not understanding it

Answer 8

@OOOPS

Answer 9

the standard form of a line is y = mx + b where m is slope of the line, b is y intercept.
among the choices, only f(x) = x has that form where m =1 and b =0. Therefore, the choice is f(x) =x
to f(x) = |x|, it's a special case whose graph is not a line. So, reject it
to f(x)= x^2, you know its graph is a parabola, not a line.
Is it clear?

Answer 10

Thanks

Answer 11

np

Answer 12

HELP STILL NOT UNDERSTANDING