i need help with this quiz!
am i correct with going with b?
yes you are right it is B.) lol
what about on this one with a? did i multiply wrong?
the restriction would be that you cannot divide by zero or have a zero in the denominator so solve for m and n when 6 m^5 n^2 = 0 and those would be your restrictions :)
no id think so
wait thats the wrong one
thats the correct one
you are correct :)
i need help with this next one i dont know if i just have to divide to finish it, i think its b
B is correct :)
u are correct lol
:) ok i guess i learned more than i though, i have 3 problems left then if you can double check my answer for 1 and 2 i would be very grateful :) i know that x + 1 would cancel out and so would the 9
and because of that i think i would be left with 4 so i think my answer would be "c" am i correct?
I Don't think it would be C because the 2/4 should simplify...
that would be a 1/2
yes, so the denominator would Not be a 4 like in C
so because x + 9 is left behind and it should have a 2 as a denominator the answer should be "b" is there any proof to this?
B would be correct :)
can you show me how i would be left with x + 9 on top?
you would simplify the 2/4 and you can cross out the (x+1) and the (x-9)
oh then it would be 1(x+9) and that would just be x+9
yep :)
:) ok this one is dealing with fractions
multiply top and bottom by 18 so you get (3+2) / (9-1) =
5 and 8
so 5/8 would be my answer
yep :)
:) ok what about this one
multiply top and bottom by 7c so \[\frac{ (8)(7c) + (3)(7) }{ (2)(7c) + 3 }\]
56 c + 21 --------- 14c + 3 ? i wouldnt multiply 3 by seven either right?
in the numerator the 3/c times 7c would equal 3 times 7 when the c's cancel out in the denominator the 3/7c times 7c would equal just 3 when the 7c's cancel out
ah i see
and I had made a slight transcription error it was supposed to be subtraction in the numerator so 56 c - 21
so my final answer would be "c"
yep :)
Thank you i just want to be sure on 2 other problem i worked before hand to be sure they are correct :)
in my book it said ( for the first problem) that if both variables equal zero the denominator would so if one = 0 then it would be 0 no matter what is my answer correct?
both are correct :)
thank you, lol i only missed one :)
dang i have to wait for my teacher to open the test on her end to see what i missed lol
well, glad I could help :) feel free to tag me if/when you need any help :D
i will :) Thank you
i will tag you when they get the site fixed lol, can you see your smart score?
I can't see any smartscores :P but mine's above a 70 by now if that was what you were wondering :)
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