Question

Which of the following is the graph of f(x) = 3 sin (2x)?

Answer 1

following?

Answer 2

use wolfram alpha, it will show the domain, range, solutions and graph

Answer 3

@nick123411

Answer 4

To figure out how to graph this, you must first know what a normal sin f(x) looks like. A normal sin graph starts at (0,0), has a period of 2pi, and an amplitude of 1. That means that the maximum height is 1 and the minimum height is -1.

So, first you want to look at the amplitude, which is the number before sin. In your case, the amplitude is 3. That means you multiply the min & max height by 3. So now your graph will go up to 3 and down to -3.

Now, you want to take a look at the 2x after the sin. By using the equation 2pi/k you can find the period. The variable k is the number before x which in your case, is 2. So now instead of your period being 2pi, it is now 2pi/2 which is pi.

So to get your intervals you basically split pi up into values of 4. So your x intervals will be 0, pi/4, pi/2, 3pi/4, and pi.

In the end your graph should look like the attached image. (Focusing from the x values of 0 through pi.

Answer 5

Refer to the attachment, the curves true shape.