Question

please help with this calculus question?

Answer 1

x = 1 is an asymptote of f

x = -1 is NOT an asymptote of f

f has a root at x = 2

the axis is an asymptote of f

the y-axis is an asymptote of f

Answer 2

@abb0t can you please help on this one?

Answer 3

anyone?

Answer 4

\[\frac{3x(x^2-x-2)}{2x(x^4-1)}\] is the first step

Answer 5

then
\[\frac{3x(x-2)(x+1)}{2x(x^2+1)(x+1)(x-1)}\] is the second

Answer 6

ooops scratch that

Answer 7

there is not a common factor of \(x-1\) top and bottom, so \(x=1\) IS a vertical asymptote

Answer 8

\(f\) has a root of \(2\) for sure, because of the factor of \(x-2\) in the numerator

Answer 9

but that would give me two choices and i can only choose one

Answer 10

which one would work?

Answer 11

the \(x\) axis IS an asymptote, as the degree fo the numerator is smaller than the degree of the denominator

Answer 12

it says "which is NOT true"

Answer 13

oh right im sorry. im looking for the one that is NOT true

Answer 14

right :)

Answer 15

ok so that means that x=-1 is NOT true right?

Answer 16

i think the last one is not true

Answer 17

x = -1 is NOT an asymptote of f <-- is true, since it's negated already

Answer 18

the y axis?

Answer 19

right lets check

Answer 20

but isn't (x+1) mean that -1 IS an asymptote of f?

Answer 21

one at a time
x = 1 is an asymptote of f this is TRUE

Answer 22

ok

Answer 23

x = -1 is NOT an asymptote of f this is TRUE

Answer 24

f has a root of x=2 i\is TRUE

Answer 25

f has a root at x = 2 is also TRUE

Answer 26

Right

Answer 27

the axis is an asymptote of f also TRUE

Answer 28

ok

Answer 29

got it

Answer 30

thank you!

Answer 31

@satellite73 one more please?