Question

Solving Radical equation help?

Answer 1

\[\sqrt{n-3}+4=2\]

Answer 2

subtract 4 from both sides first, what do u get ?

Answer 3

I got n=7, but when I plug it in, I get 6

Answer 4

there is something special here your not seeing

Answer 5

yes, you got n =7 correctly, but

Answer 6

can a value of square root be negative ?

Answer 7

no

Answer 8

so, you have
\(\sqrt{n-3}=-2\)
is that even possible ?

Answer 9

oh no, so no solution?

Answer 10

correct! :)

Answer 11

Yay, thanks so much ;D

Answer 12

welcome ^_^

Answer 13

\[\sqrt{x+6}=\sqrt{3x-8}\] On this one I just square both and combine like terms right?

Answer 14

yes!

Answer 15

and in this too, you need to verify whather the 'x' value you get is actually the solution or not.

Answer 16

no solution because I get x=-0.5

Answer 17

how ?

Answer 18

I combiined like terms, x+6=3x-8 x+3x=4x 6-8=-2

Answer 19

-2 divided by 4 = -0.5

Answer 20

not like that

Answer 21

to combine terms, they should be on same side of =

x+6 = 3x-8
subtract x from both sides

Answer 22

Ohh right, ok;)

Answer 23

so it is x=7

Answer 24

Thanks ;D

Answer 25

yes!

Answer 26

welcome ^_^