Question

Find the value of Q in the following system so that the solution to the system is {x,y):x-3y=4}

x-3y=4

Qx-6y=8

Answer 1

i think i can help

Answer 2

are you there?

Answer 3

Seems that you may of left something out. Do you have the values of x and y that this particular system should give?

Answer 4

No thats all that the problem gives /:

Answer 5

Okay ill give it a go.

Answer 6

Q = 2

Answer 7

\[x-3y=4\]
\[y = \frac{x-4}{3}\]
\[Qx- 6(\frac{x-4}{3})= 8\]
\[Qx -2(x-4) = 8\]
\[Qx-2x+8=8\]
\[x(Q-2) = 0\]
\[Q-2=0\]
\[Q=2\]

Answer 8

Thank youu ! much appreciated(: