Question

Calculus? Use implicit diferentiation to find dy/dx for sin x^3 = cos y ^2

Please help?

Answer 1

The derivative of the left side (with respect to x -- d/dx) is 3x^2 cos(x^3). The derivative of the right side (again, with respect to x) is -2y sin(y^2)(dy/dx). Solving for dy/dx yields:\[=\frac{3x^2\cos(x^3)}{-2y \sin(y^2)}\]

Answer 2

great thank you :)

Answer 3

yw

Answer 4

could you help me on one more?

Answer 5

how do i solve this?

Answer 6

@BTaylor please tell me, can you help?