How do I compute the sample mean difference in weight?
if im remembering; its pretty much taking the difference between 1 weight from all the others; then doing the same for another, then another, until all weights have been differenced from every other weight ; then divide by how many times you had to do it
but without some more context, thats the best idea i got :)
I know I have a right (4.167 or 4.2 lbs.) But I am stuck on B and C
row 3 is the data set
\[\sigma\approx s^2/\sqrt n\] hmm, id have to chk this but thats when im thinking for standard error im thinking s is an unbiased estimator of sigma for the sample
s/sqrt(n) ... not s^2
you do know how to calculate a sample standard deviation right?
I am jsut not understanding how to get B. I know that whatever my answer is from B is divided by the sq oot of n to get c.
what was the sample mean?
\[\large s=\frac{\sum(x-\bar x)^2}{n-1}\]
Thank you :) I think I can get it from here...we'll see.
the sample standard deviation is a biased estimator but is commonly used as a point estimator of the populations standard deviation. Otherwise it might be expecting a chi^2 distribution
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