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what is the inverse of f if f(x)=^3 sqrt(x-5) answers: f^-1(x)=x^3+5 f^-1(x)=1/ ^3 sqrtx-5 f^-1(x)=x^3+125 f^-1(x)=5-^3 sqrtx
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to solve for the inverse you should flip your x and y and solve for x where f(x)=y
but idont see a y
\[y=\sqrt[3]{x-5}\] \[x=\sqrt[3]{y-5}\] there
then \[x^3=y-5\\ x^3+5=y\] and that is your inverse
so a?
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i stated where f(x)=y
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