Check my answer please.
Find the zeros of f(x) = x2- x - 6 by using a table and a graph. Enter the largest zero. Use a number only.
I got -1 for the largest Zero
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jimthompson5910 (jim_thompson5910):
Let's check that answer. Plug in x = -1 to get
f(x) = x^2 - x - 6
f(-1) = (-1)^2 - (-1) - 6 ... replace EVERY x with -1
f(-1) = 1 - (-1) - 6
f(-1) = 1 + 1 - 6
f(-1) = 2 - 6
f(-1) = -4
Notice how the result is NOT zero, so that means that x = -1 is NOT a root or zero of f(x)
OpenStudy (darkbluechocobo):
Wouldn't they both be negative though (x-1) (x+6) so its 6 sorry
OpenStudy (darkbluechocobo):
wait no
jimthompson5910 (jim_thompson5910):
x^2 - x - 6 doesn't factor to (x-1) (x+6)
OpenStudy (darkbluechocobo):
Yes just realized.
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OpenStudy (darkbluechocobo):
-3 and 2
jimthompson5910 (jim_thompson5910):
check each one
OpenStudy (darkbluechocobo):
3 -2
OpenStudy (darkbluechocobo):
because it works out that way
OpenStudy (darkbluechocobo):
-2^2= 4
4+2=6
6-6=0
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OpenStudy (darkbluechocobo):
3^2=9
9-3=6
6-6=0
OpenStudy (darkbluechocobo):
so i believe the answer would be 3
jimthompson5910 (jim_thompson5910):
very good, you got it
OpenStudy (darkbluechocobo):
Thank you :D
jimthompson5910 (jim_thompson5910):
you're welcome
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OpenStudy (darkbluechocobo):
Find the zeros of the function h(x) = 3x2 + 13x + 4 by factoring.
4, -1/3
4, 1/3
-4, 1/3
-4, -1/3
Ok I did some more but then I got to this one and was like Wahhhhhhhh
OpenStudy (darkbluechocobo):
Could you assist me
jimthompson5910 (jim_thompson5910):
if factoring is a pain, you could use the quadratic formula to solve