Solve 3p^2 = -8p -5
do you know the first step?
i need to get the equation to one side
good job so what do you need to do so one part of the equation can be in one side?
add -8p -5 or subtract -3p^2
close but first you need to put all the numbers together and the variables in the other side so now do you know what to do?
no I'm confused
yes but how does that relate to my problem?
it's exactly what the problem is but different number and variable it's not that you don't understand it's that you want the answer instead of doing the work
haha no i don't…..i know my homework is based on what we learned in class and this is not what i learned. and i want to "do the work: so i know how to do the work on my test...
and the example i gave you was exactly what your question is but different number and variable once again so you should be able to understand this.
okay its just I'm suppose quadratic formula, completing the square or simple factoring but idk what aim doing wrong
and i already know the answer to the question
so what is it?
-1 and -5/3 i know the answer but i want to know how to get it
i'm done how do you know the answer if you don't know how you got it
my book gives the answer to the odd questions so you can check your work...
3p^2 = -8p -5 Add (8p+5) to both sides: 3p^2 + 8p + 5 = 0 3p^2 + 3p + 5p + 5 = 0 Can you factor it from here on?
how did you get 3p + 5p? did you split the middle?
3p^2 + 8p + 5 = 0 multiply a and c (ax^2 + bx + c = 0) 3 * 5 = 15 split 15 into two factors such that their sum is 8 you can try 1 x 15 (that won't work) 3 x 5 (will work, their sum is 8 and their product is 15). so 3p^2 + 3p + 5p + 5 = 0
oh okay thank you but i have one more question how do i know when to use the quadratic formula, completing the square or just simple factoring?
completing the square is not usually used for solving a quadratic equation. It is usually done to put the equation of a parabola in a vertex form. Solving for x (or find the roots or zeros of a quadratic equation) the choice is usually between factoring ans using the quadratic formula. I will attempt factoring first. And if there is no easy factoring then I will resort to the quadratic formula.
okay thank you!
you are welcome.
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