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Mathematics 21 Online
OpenStudy (anonymous):

Really need some help on this question :L Pls help for a medal and fan

OpenStudy (anonymous):

Regan is trying to find the equation of a quadratic that has affocus of (-2,5) and a directrix of y=13. describe to regan your preferred method for deriving the equation. make sure you use regans situation as a model to help her understand

OpenStudy (anonymous):

ok let me check it out c:

OpenStudy (anonymous):

um its confusing haha sorry i really suck at math as you can tell :/

OpenStudy (btaylor):

Sorry. I haven't done any of this before. I'll try to work through this with you.

OpenStudy (anonymous):

ok thank you so much :/

OpenStudy (anonymous):

can someone help me? http://openstudy.com/study#/groups/Literature

OpenStudy (btaylor):

If the focus of a parabola is (-2, 5) and the directrix is y = 13, find the equation of the parabola. Let ( x0 , y0 ) be any point on the parabola. Find the distance between (x0 , y0) and the focus. Then find the distance between (x0 , y0) and directrix. Equate these two distance equations and the simplified equation in x0 and y0 is equation of the parabola. The distance between (x0 , y0) and (-2, 5) is \[\sqrt{(x_0-(-2))^2+(y_0-5)^2}\]

OpenStudy (anonymous):

okk

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