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Mathematics 21 Online
OpenStudy (anonymous):

how would you solve this inequality?

OpenStudy (anonymous):

\[5>\sqrt{2y+7}\]

OpenStudy (anonymous):

square both sides to remove the radical sign...

OpenStudy (anonymous):

so then it would be 25>2y+7?

OpenStudy (anonymous):

after which you can proceed the usual way of solving inequality...

OpenStudy (anonymous):

would the answer be 9>y?

OpenStudy (anonymous):

i mean y>9

OpenStudy (agent0smith):

You were right before you corrected it.

OpenStudy (anonymous):

yup... you can check it for any values of y>9....

OpenStudy (agent0smith):

9>y and also you have to make sure 2y+9>0 - since you can't take the square root of a negative number

OpenStudy (anonymous):

oh yes i agree with @agent0smith ...

OpenStudy (anonymous):

oh okay i see, thank you!

OpenStudy (agent0smith):

since if you just have 9>y, you could choose something like y=-10, then 2y+7 will be -13, which doesn't have a real solution

OpenStudy (anonymous):

the range of y must be -4<y<9 to satisfy the original inequality... to assure that 5 > sqrt(2y + 7)...

OpenStudy (agent0smith):

2y+9>0 would give y>-4.5, not -4, but otherwise you're right :)

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