how would you solve this inequality?
\[5>\sqrt{2y+7}\]
square both sides to remove the radical sign...
so then it would be 25>2y+7?
after which you can proceed the usual way of solving inequality...
would the answer be 9>y?
i mean y>9
You were right before you corrected it.
yup... you can check it for any values of y>9....
9>y and also you have to make sure 2y+9>0 - since you can't take the square root of a negative number
oh yes i agree with @agent0smith ...
oh okay i see, thank you!
since if you just have 9>y, you could choose something like y=-10, then 2y+7 will be -13, which doesn't have a real solution
the range of y must be -4<y<9 to satisfy the original inequality... to assure that 5 > sqrt(2y + 7)...
2y+9>0 would give y>-4.5, not -4, but otherwise you're right :)
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