Question

@jessiehuang_ Evaluate 5(a – 2b) when a = –3 and b = 5.



A.


65


B.


35


C.


–65


D.


–25

Answer 1

@jessiehuang_

Answer 2

@jessiehuang_

Answer 3

-65

Answer 4

5(a - 2b) a = -3, b = 5
substitute your values of a and b into your expression
5(-3 - 2(5))
5(-3-10)
5(-13)
-65

Answer 5

Evaluate –6(x – 2y) when x = –3 and y = –5



A.


–42


B.
80


C.


–80


D.


–16

Answer 6

-42

Answer 7

these are not that hard to do...just sub in your values into the expression and solve mathematically.
jessie..be careful just giving answer...you can get booted off for that

Answer 8

Simplify: (–5) • (7) – (6) • (–2)



A.


–23


B.


–35


C.


10


D.


47

Answer 9

oh i'm sorry, i'm multi-tasking with my english homework and open study, i'll try and show explanations from now on @kelliegirl33 but thanks for the heads up :)

Answer 10

Simplify: (–5) • (7) – (6) • (–2)



A.


–23


B.


–35


C.


10


D.


47

Answer 11

no problem...I learned the hard way and got booted for 2 weeks by just giving answers

Answer 12

Simplify: (–5) • (7) – (6) • (–2)



A.


–23


B.


–35


C.


10


D.


47

Answer 13

ok just multiply from left to right;
-5*7=-35
-(-6)*(-2)=12
combine:
-23

Answer 14

so its A

Answer 15

yes

Answer 16

Simplify: –5(x – 3) + 2(a – 9)



A.


–5x + 2a + 33


B.


–5x + 2a + 4


C.


–5x + 2a – 3


D.


–5x + 2a – 33

Answer 17

ok so distribute both parenthesis: -5x+15+2a-18
rearrage: -5x+2a+15-18
combine like terms: -5x+2a-3
so c

Answer 18

Simplify: –6(x – 3) – 4(y + 5) + (–5)(7 – 2b)



A.


–6x –4y – 10b – 3


B.


–6x –4y + 10b – 37


C.


–6x –4y + 10b + 3


D.


–6x –4y + 10b + 33

Answer 19

–6(x – 3) – 4(y + 5) + (–5)(7 – 2b)
distribute: -6x+18-4y-20-35+10b
rearrange: -6x-4y+10b+18-20-35
combine like terms: -6x-4y+10b-37
b

Answer 20

oh

Answer 21

u got me 100% again omg u should be a mod

Answer 22

close and reopen ok

Answer 23

just make sure to tag.

Answer 24

ok

Answer 25

Which equation could be used to solve this problem?



The sum of two consecutive integers is 141. Find the integers.



A.


n + 1= 141


B.


2n + 2 = 141


C.


2n = 141


D.


2n + 1 = 141