Question

Thanks so much!

Answer 1

Do you have a formula?

Answer 2

Do you know the point slope formula?

Answer 3

It's okay=) I am not sure how to approach this... I am sorry I wasn't able to help out.

Answer 4

Hmm as travel time (x) increases,
the Speed (y) is decreasing.

So they do seem to be inversely proportional, yes?
As one goes up, the other goes down.

So we'll write that relationship:\[\Large y\quad=\quad \frac{k}{x}\]Where k is some constant of proportionality.
We can figure out what k is based on the chart.

Answer 5

Let's use one of the coordinate pairs to solve for k.
Plugging in: \(\Large (x,\;y)=(36,\;50)\)
Try to solve for k.

Does that make sense? :o

Answer 6

You have to first be able to recognize that x and y are inversely related ( as one goes up, the other is getting smaller).

Then you have to remember what an inverse relationship `looks like`.\[\Large\bf y\quad=\quad \frac{k}{x}\]^ That gives us our relationship between x and y.
Now we plug in one of the points to figure out our k.\[\Large\bf (x,\;y)=(36,\;50)\]Plugging in gives us:\[\Large\bf 50\quad=\quad \frac{k}{36}\]

Answer 7

Understand how to solve for k from that point? :o

Answer 8

25k/18

Answer 9

25=k/18

Answer 10

Hmm no that's no bueno :(
If you divide a 2 out of each side, denominator on the right side will actually get bigger.\[\Large\bf 50\quad=\quad \frac{k}{36}\]We want to solve for k, but there's a 36 dividing it.
Maybe if we multiply both side by 36? :o

Answer 11

Okay I get what you're saying but I'm most than likely doing it all wrong lol, you're suppose to mutiple 50 and 36 by 36? That gives me ridiculous numbers? Sorry coming off as dull I'm just new to this whole thing

Answer 12

If you multiply the 50 by 36, yes it gives you a large number :)
But that's ok, that's a good number.\[\Large\bf 36\cdot50\quad=\quad \frac{k}{\cancel{36}}\cdot\cancel{36}\]But on the right side, we are dividing AND multiplying by 36, so they will "cancel out".

Answer 13

\[\Large\bf k\quad=\quad 36\cdot50\quad=\quad ?\]So what do we get for k?

Answer 14

\[\Large\bf y\quad=\quad \frac{k}{x}\]Ok good. We'll plug that value back into the missing k value in our inverse relationship.\[\Large\bf y\quad=\quad \frac{1800}{x}\]

Answer 15

Now as a final step, they want us to figure out the `speed (y)` when x=40.

Answer 16

\[\Large \frac{1800}{40}\ne 50\]

Answer 17

Yayyy good job \c:/

So we've figure out the relationship between x and y.
And we found that when x is 40, y is 45.

Answer 18

So we had to answer the first part rather quickly, because the rest of it is a lot of work to get through.

Yes, we looked at the table of data, each x value corresponds to the y value directly below it.
x=36 corresponds to y=50.
x=50 corresponds to y=36.

Hmm see how as x increases, y decreases?
That tells us that they're inversely related to one another.
Yah that answers the first part.

Then the next part was a bit tricky.

Answer 19

The inverse equation started out as this:\[\Large\bf y\quad=\quad \frac{k}{x}\]But it was complete when we found our k value,\[\Large\bf y\quad=\quad \frac{1800}{x}\]

We then used the equation to find y when x=40. :d
I hope that's making a little bit of sense.

Answer 20

yay team \c:/

Answer 21

Oh and,
\(\Large \color{royalblue}{\text{Welcome to OpenStudy! :)}}\)