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Suppose that 3<=f'(x)<=5 for all values of x. Show that 18<=f(8)-f(2)<=30
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\[3\le f'(x)\le5\]
\[18\le f(8)-f(2)\le30\]
mean value theorem
which is
look it up...you need it to do this problem
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i have the theorem bu ti don't get how it applies
look at \[\frac{f(8)-f(2)}{8-2}=f'(c)\] \[2<c<8\]
i still don't get how that helps me find 18≤f(8)−f(2)≤30
think about it for a little bit...if I do any more I will be doing the entire problem
i am not good at math. i never understand it
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