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Mathematics 13 Online
OpenStudy (anonymous):

I NEED HELP! GIVING MEDALS! w/AttachedPhoto

OpenStudy (anonymous):

jigglypuff314 (jigglypuff314):

assuming it is a kite and has the properties of a kite... CV = 20/2 = then Pythagorean theorem UV^2 = CV^2 + CU^2 so UV = √(CV^2 + CU^2) so UV = √(10^2 + 12^2)

OpenStudy (anonymous):

15.62? :D

jigglypuff314 (jigglypuff314):

that's what I got ;)

OpenStudy (anonymous):

Thanks!

jigglypuff314 (jigglypuff314):

angle TUV = angle TUW + angle VUW so angle TUV = (10x - 7) + (5x + 13)

OpenStudy (anonymous):

x+4?

jigglypuff314 (jigglypuff314):

? how did you get that?... angle TUV = (10x - 7) + (5x + 13) = 10x - 7 + 5x + 13 = 10x + 5x + 13 - 7

OpenStudy (anonymous):

15x+5 Then what?

jigglypuff314 (jigglypuff314):

13-7 = 6 so 15x + 6 should be your answer I think...

OpenStudy (anonymous):

oyeah. xD

OpenStudy (anonymous):

Last one @jigglypuff314 Thank you for your help! :D

jigglypuff314 (jigglypuff314):

Pythagorean theorem TU^2 = TC^2 + CU^2 so TC^2 = TU^2 - CU^2 so TC = √(TU^2 - CU^2) = √(10^2 - 6^2)

jigglypuff314 (jigglypuff314):

since I gtg 8 would be correct ;)

OpenStudy (anonymous):

Thanks! Good day! Have a happy thanksgiving!

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