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OpenStudy (anonymous):
I NEED HELP! GIVING MEDALS! w/AttachedPhoto
12 years ago
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OpenStudy (anonymous):
12 years ago
jigglypuff314 (jigglypuff314):
assuming it is a kite and has the properties of a kite...
CV = 20/2 =
then Pythagorean theorem
UV^2 = CV^2 + CU^2
so UV = √(CV^2 + CU^2)
so UV = √(10^2 + 12^2)
12 years ago
OpenStudy (anonymous):
15.62? :D
12 years ago
jigglypuff314 (jigglypuff314):
that's what I got ;)
12 years ago
OpenStudy (anonymous):
Thanks!
12 years ago
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jigglypuff314 (jigglypuff314):
angle TUV = angle TUW + angle VUW
so angle TUV = (10x - 7) + (5x + 13)
12 years ago
OpenStudy (anonymous):
x+4?
12 years ago
jigglypuff314 (jigglypuff314):
? how did you get that?...
angle TUV = (10x - 7) + (5x + 13)
= 10x - 7 + 5x + 13
= 10x + 5x + 13 - 7
12 years ago
OpenStudy (anonymous):
15x+5
Then what?
12 years ago
jigglypuff314 (jigglypuff314):
13-7 = 6
so 15x + 6 should be your answer I think...
12 years ago
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OpenStudy (anonymous):
oyeah. xD
12 years ago
OpenStudy (anonymous):
Last one @jigglypuff314 Thank you for your help! :D
12 years ago
jigglypuff314 (jigglypuff314):
Pythagorean theorem
TU^2 = TC^2 + CU^2
so TC^2 = TU^2 - CU^2
so TC = √(TU^2 - CU^2)
= √(10^2 - 6^2)
12 years ago
jigglypuff314 (jigglypuff314):
since I gtg
8 would be correct ;)
12 years ago
OpenStudy (anonymous):
Thanks! Good day! Have a happy thanksgiving!
12 years ago
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