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please help! 3 − (2x − 5) < −4(x + 2)
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3-(2x-5)<-4(x+2) 3-2x+5<-4x-8 -2x+4x<3-8+5 2x<3-8+5 2x<-5+5 2x<0
i think thats how you do that
ok thanks so much
3 − (2x − 5) < −4(x + 2) = 3 - 2x + 5 < -4x - 8 = -2x + 2 < -4x - 8 Divide equation by -2, [change the inequality thus] = x - 1 > 2x + 4 = -5 > x Or x < -5 @MexicanHoneyBadger 's solution is not correct.
cool thanks
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