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Geometry 16 Online
OpenStudy (anonymous):

ED is perpendicular to EC; BD is perpendicular to BC; ED is congruent to BC. Prove Triangle CED congruent to Triangle DBC

OpenStudy (anonymous):

|dw:1385688872006:dw| So it looks likes this kind of?

OpenStudy (anonymous):

You can use the Angle side Angle thoerm

OpenStudy (anonymous):

I mean side angle side BC and De Are a side the angle they share is 90 degree angles that is bisected to make triangles, and the DC is a shared side

Directrix (directrix):

I think SAS is not correct because the right angles are not included between the two congruent sides. |dw:1385689291475:dw|

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