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Mathematics 25 Online
OpenStudy (lena772):

I calculated the y-intercept but idk what it tells me

OpenStudy (lena772):

hartnn (hartnn):

your y-intercept means when x= 0 here, x represents time time = 0 means initially so, y-intercept gives you INITIAL VELOCITY of the car

hartnn (hartnn):

that is the velocity with which the car started

hartnn (hartnn):

so the car started with 50miles/hr

OpenStudy (lena772):

Thank you! for the next one the equation is f(b)-f(a)/b-a?

hartnn (hartnn):

yes, that formula is correct

OpenStudy (lena772):

so i don't have a function here what do i do

hartnn (hartnn):

y = f(x) its like, f(b) means 'y' value at b

hartnn (hartnn):

so f(3) means y value or velocity at x= 3 hrs

hartnn (hartnn):

you got what i am trying to explain ?

OpenStudy (lena772):

f(3)-f(1)/3-1

hartnn (hartnn):

yes, and what are f(3) and f(1) ?

OpenStudy (lena772):

that's what idk :( ik you explained but i still dont know what to do

hartnn (hartnn):

we take f(x) as 'y' so, f(3) means y value when x = 3 which = ... ?

hartnn (hartnn):

see the table, what is y when x= 3 ?

OpenStudy (lena772):

oh it's 56

OpenStudy (lena772):

56-52/3-1

OpenStudy (lena772):

4/2 2

hartnn (hartnn):

yes

hartnn (hartnn):

correct and you know what it represents ?

OpenStudy (lena772):

2 miles per hour

OpenStudy (lena772):

The car increases it's speed by 2 miles per hour after every hour.

OpenStudy (lena772):

@hartnn

hartnn (hartnn):

yes, that means the rate of change of velocity is 2 miles/hour^2 which is actually the ACCELERATION of the car

hartnn (hartnn):

so, average rate of velocity represents the accelration

OpenStudy (lena772):

domain would be 4 right for C?

hartnn (hartnn):

when x = 4, is y = 60 ? and domain is the set of values, not just 1 value

OpenStudy (lena772):

ohsorry :/

OpenStudy (lena772):

when x=4 y=58, when x=5 y=60

OpenStudy (lena772):

[50<x<60]?

hartnn (hartnn):

yes, so x is 5 when y is 60 and domain is the set of "x" values (set of y values is actually the RANGE) so here, your domain will be x = 0 to 5

OpenStudy (lena772):

but dont you have to say [0<x<5]

hartnn (hartnn):

thats just a way to represent(interval notation), you can represent it in may ways

OpenStudy (lena772):

sorry if i'm being anoying

hartnn (hartnn):

and thats not correct

hartnn (hartnn):

i mean not accurate

OpenStudy (lena772):

annoying*

OpenStudy (lena772):

ok so I just put domain: 0 to 5

OpenStudy (lena772):

The domain would be integers from 0 to 5.

hartnn (hartnn):

\(0 \le 0 \le 5\)

hartnn (hartnn):

i mean 0 <= x <= 5

hartnn (hartnn):

my point was just that u missed the "=" as x can actually take the values, 0 and 5

OpenStudy (lena772):

oh but i thought [] those represented could be equal

hartnn (hartnn):

thats another notation

hartnn (hartnn):

\([0,5]\)

hartnn (hartnn):

\(0\le x \le 5 \\ [0,5]\) both are same

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