3. Solve the equation and write the solution set. |2x – 6| – 4x = 8x + 4
this is the only question i cant seem to find the right answer for! can someone please help?
Do you have options to chose from?
no, thats all it gave me.
kk, sec
I got -10x/10 = 10/-10
x=-1
Yup :D
okay thanks! :) and how did you get that?
l2x - 6l -4x = 8x + 4 + 4x + 4x 2x - 6 = 12x + 4 + 6 + 6 2x = 12x + 10 -12x - 12x -10x = 10 /-10 /-10 = -1
well done fizzy...and sara i hope ths guy let u to understand thorouly
Fizzy? =.=
@sarahann117 did you understand?
fizzi which is the best free software for mathmetics,i e Calculus,fouriour n Laplace Transforms???
I'm a freshman lol I can't take calculus yet.. sorry :/
ok fizzy in which level r u studying?
What do you mean?
i mean in which class r u studying?
Algebra I. though I practice more advance stuff when I'm not doing HW. I'm kinda learning physics too :)
ok but i am studying advance Engineering Mathmetics ...only applied in Electrical Engineering
Have you looked at mathway.com?
yes it is good website but u can also try integrals.wolfram.com/ and Quickmath.com as well
Yes I've done a few other problems like this one but i forgot to carry over, thanks though!(:
Yea, saw them on google :D @sarahann117 Yw :)
ok dear thanks u so much,,,if u are using facebook too here is my id skywalker763@yahoo.com u can add me their
xD sure .. I forgot my fb password and possible email ._.
ok i hope u ll add whenever u ll make ur new account on fb
kk cyaa :p
@sarahann17 This kind of equations requires taking in consideration intervals of x for the absolute value of the expression |2x-6| . Case 1: when 2x-6>=0 ie. x>=3 The answer is like @tHe_FiZiCx99 and @hasnain986 said : x=-1 But -1<3, meaning the answer doesn't belong in the interval. Therefore, there's no solution on this interval. Case 2: when 2x-6<=0 ie x<=3 |2x-6| - 4x = 8x + 4 becomes -(2x-6) - 4x = 8x + 4 The answer to that is x=1/7 And 1/7<=3, meaning the answer belongs in the interval. So the solution set: S={1/7}
@sarahann117 *
I also got 1/7 when I tried to find the interval. forgot to include it though Ty @math&ing001
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