GIVING A MEDAL! w/PhotoAttached
This is an isosceles right triangle (it has two equal legs and two equal interior angles plus a right angle. Thus, the Pythagorean theorem applies. If one of the legs has length 7Sqrt(2), then the other leg is of the same length. Find the square of the length of one leg. Double this (because there's another leg of equal length). Find the square root of this sum; it's the length (x) of the hypotenuse.
Use trigonometry (7sqrt2)/x = sin(45) x = (7srt(2))/(sqrt2/2) =14 Hope this helps :)
if you still need help: familiar with SOH, CAH, TOA?
You can use the "special 45-45-90 triangle" to answer this see http://www.regentsprep.org/Regents/math/algtrig/ATT2/Ltri45.htm the long side (the hypotenuse) is sqr(2) times the length of one of the legs (each leg is the same length)
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