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Geometry 16 Online
OpenStudy (anonymous):

How to find A line segment that has a perpendicular bisector

ganeshie8 (ganeshie8):

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ganeshie8 (ganeshie8):

thats a segment AB wid perpendicular bisector

OpenStudy (anonymous):

@ganeshie8 can you find that ? :/

ganeshie8 (ganeshie8):

Yes, you need to find the line segment. NOT the perpendicular bisector ok.

ganeshie8 (ganeshie8):

look at the graph, which line segment has end points as (-2, 2) and (4, -4) ? can u tell ? :)

OpenStudy (anonymous):

i chose c and d but im not sure because c has -2,2 and 4,-4 but d's line passes through it @Ganeshie8

ganeshie8 (ganeshie8):

very good observation ! see that option d is longer than the segment we're looking for. It doesnt have the endpoints as (-2, 2) and (4, -4)

ganeshie8 (ganeshie8):

we want a segment wid END-POINTS as (-2, 2) and (4, -4) not just a segment which passes thru them.

ganeshie8 (ganeshie8):

oops ! i made a mistake in interpreting the question. hang on a sec

OpenStudy (anonymous):

@ganeshie8 thank you for your help!

ganeshie8 (ganeshie8):

C is definitely one answer. lets see if d also is the answer,

ganeshie8 (ganeshie8):

linesegment in graph d :- (-4, 4) (7, -7) find its midpoint, -4+7 ----- = 3/2 2 4 - 7 ----- = -3/2 2

ganeshie8 (ganeshie8):

which is NOT same as (1, -1) which u have worked before. so oly C is the answer :)

ganeshie8 (ganeshie8):

see if that makes some sense

OpenStudy (anonymous):

THANK YOU! I appriciate it. :) @ganeshie8

ganeshie8 (ganeshie8):

np :)

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