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Mathematics 23 Online
OpenStudy (anonymous):

Statement 1: "If she is stuck in traffic, then she is late." Statement 2: "If she is late, then she is stuck in traffic." Statement 3: "If she is not late, then she is not stuck in traffic." Karen writes, "Statement 2 is the converse of statement 3 and contrapositive of statement 1." Laura writes, "Statement 2 is the converse of statement 1 and inverse of statement 3."

OpenStudy (anonymous):

Which option is true? Both Karen and Laura are incorrect. Only Laura is correct. Both Karen and Laura are correct. Only Karen is correct.

OpenStudy (haseeb96):

ONLY LAURA IS CORRECT

OpenStudy (anonymous):

Only laura is correct

OpenStudy (anonymous):

That's what I thought it would be. Thanks :)

OpenStudy (anonymous):

:)

OpenStudy (ybarrap):

Laura is correct because Let P = she is stuck in traffic Let Q = she is late Statement 1: "If she is stuck in traffic, then she is late." \(P\rightarrow Q\) Statement 2: "If she is late, then she is stuck in traffic." \(Q\rightarrow P\) Statement 3: "If she is not late, then she is not stuck in traffic." \(\neg P\rightarrow \neg Q\) Karen says "Statement 2 is the converse of statement 3 and contrapositive of statement 1." In other words, she says that Statement 2 is logically \(\neg P \rightarrow \neg Q\) and \(\neg Q \rightarrow \neg P\) which means that "She is not late iff she is not stuck in traffic", which is not what statement 2 means, logically. Laura says "Statement 2 is the converse of statement 1 and inverse of statement 3." In other words, she says that Statement 2 logically \( Q \rightarrow P\) and \( Q \rightarrow P\), which are ,of course, the same and is logically true.

OpenStudy (ybarrap):

*Statement 3 should be \(\neg Q \rightarrow \neg P\), everything else is correct.

OpenStudy (anonymous):

That helped me understand it a lot more .

OpenStudy (anonymous):

Thank you.

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