Question

let F(x)=5/x and g(x)=2x^2+5x. What two numbers are not in the domain of f o g?

A. 0,-5/2
B. 0,-2/5
C. 0, 2/5
D. 0, 5/2

Answer 1

@robinnicole218

Answer 2

@adrouin1

Answer 3

@jdoe0001

Answer 4

\(\bf f(x)=\cfrac{5}{x} \qquad g(x)=2x^2+5x\\ \quad \\
fog\implies f(\quad g(x)\quad )=\cfrac{5}{(2x^2+5x)}\)

for rationals, the domain is constrained to values that will not make the fraction undefined
a fraction or rational is undefined when the denominator is 0, thus
any values in this case "x" can take MUST NOT make the denominator expression to 0

Answer 5

so if you solve \(\bf 2x^2+5x=0\) to find the values of "x", those values, notice the =0 part, will make the denominator 0, and those are the values "x" MUST NOT take
and thus the domain constraints

Answer 6

0,-5/2 right @jdoe0001

Answer 7

yeap

Answer 8

ty

Answer 9

yw