convert polar equation into cartesian equation

r=-4tan(theta)sec(theta)

help?

Question

convert polar equation into cartesian equation 

r=-4tan(theta)sec(theta)

help?

anonymous · Answer

i've gotten as far as $$\frac{ -4\tan(\theta) }{ \cos(\theta) }=r$$

$$rcos(\theta)=-4\tan(\theta)$$

$$x=-4\tan(\theta)$$

anonymous · Answer

but now i'm stuck.  can't figure how to get y=mx+b

anonymous · Answer

there are conversion formulas between polar and rectangular...

anonymous · Answer

which are?  the one's i've got don't help me

anonymous · Answer

$r^2=x^2+y^2$

anonymous · Answer

that doesn't help me...

anonymous · Answer

$$y=rsin \theta$$

anonymous · Answer

i have both of those.

anonymous · Answer

$x=r~cos~theta$

anonymous · Answer

ok, yes, i have all of those.  i can't use any of them.....................listing equations i already have isn't helping....

anonymous · Answer

of course you have to plug it all in the formula...

anonymous · Answer

what i mean to your given problem...

anonymous · Answer

i did.  which left me with x=-4tan(theta)...like i said before.  i'm stuck there.  i need y=mx+b...

anonymous · Answer

can I say something?

anonymous · Answer

will go to that later, first we have to transform the equation in x and y only...

anonymous · Answer

yes @OOOPS ... :)

anonymous · Answer

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