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Mathematics 22 Online
OpenStudy (idku):

Logarithm question.

OpenStudy (idku):

\[Log _{(Log_5x)}\]is there any way to simplify this?

OpenStudy (kc_kennylau):

Sorry but no :/ (just according to my knowledge)

OpenStudy (kc_kennylau):

@hartnn sorry I have to sleep now see you next week :D

OpenStudy (idku):

I have another question about economics, can you help me with it? http://openstudy.com/study#/updates/529b5a8fe4b0e39d4e828bc1

OpenStudy (idku):

After this q of course.

hartnn (hartnn):

idku the log has base of (log_5 x) ?? than what are you taking log of ? or is it \(\large \log_{\log5}x\) i'd say the question is unclear...

OpenStudy (idku):

I wrote it incompletely, sorry. \[Log _{(Log_5x)}x\]

hartnn (hartnn):

ok, so we need change of base rule \(\large \log_ab = \dfrac{\log b}{\log a}\) so how will u use it in your question?

OpenStudy (idku):

I though that in my question where it's equal to zero, I can say, \[Log _{Log_5x}x=0~~~~~~~~~->~~~~~~~~~~~Log _{Log_5x}x=Log_{Log_5x}1\]so x =1 Right?

hartnn (hartnn):

no, x cannot be 1 if x= 1 the base of the log, which is log_5 x will become =0 and base of log cannot =0

OpenStudy (idku):

true, so how would I solve it then?

hartnn (hartnn):

you have to solve for x in that equation with = 0 ? after solving you indeed get x=1 when we plug back in x=1, we find that x cannot =1 this means that x=1 is an ENTRANEOUS solution and there is actually no solution for that equation

OpenStudy (idku):

Thank you!

hartnn (hartnn):

welcome ^_^

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