Question

how do I solve 4cos(x+4)=1?

Answer 1

\(\bf 4cos(x+4)=1\implies cos(x+4)=\cfrac{1}{4}\\ \quad \\
\implies cos^{-1}[cos(x+4)]=cos^{-1}\left(\cfrac{1}{4}\right)\)

Answer 2

recall that \(\bf cos^{-1}[cos(\theta)]=\theta\)

Answer 3

\[Cos(x+4) = \frac{ 1 }{ 4 }\]
\[x+4 = Cos ^{-1}(1/4)\]
\[x = Cos ^{-1}(1/4) -4\]

And you need to use the calculator to find the value of arc cos(1/4)

Answer 4

okay thank you that helped a lot!