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calculus question:
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|dw:1385945260921:dw|
I don't know how to find the derivative.
1/3(8-t^8)^-1/3?
|dw:1385945434207:dw|
I don't know.
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It'd be helpful if you'd please label this. Do you mean f(x) = Cuberoot(8 - t^8)? Why the (-) sign in the exponent? That 1/3 does not adequately indicate that you're looking for the cube root. I'd suggest sticking to spelling out the word (Cuberoot) or drawing it (as you've already done).
is this your question? \[\large \sqrt[3]{8-t^{8}} = (8-t^{8})^\frac{ 1 }{ 3}\]
yes!
From there use the product and chain rule then :)
the power* and chain rule*
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watermelon: You've got this partially correct, but have neglected to find the derivative of (8 - t^8) as required by the chain rule.
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