Question

Integration
(Putting into equation)

Answer 1

\[\int\limits_{}^{}\frac{ x^{2} }{ 3x^{3}+8 }dx\]

Answer 2

Make the change of variable
\[

u= 3 x^3 +8
\]

Answer 3

x^2/u and what from there? o.O 2x/u? lol the answer choices have absolute value and im not sure how they got that.

Answer 4

\[
du = 9 x^2 dx\\
\frac {du}9=x^2 dx\\

\int \frac {x^2 dx}{3x^3 +8}= \frac 1 9 \int \frac{du}{u}=\frac 1 9 \ln|u| + C=\\
\frac 1 9 \ln|3 x^3 +8| + C

\]

Answer 5

RIGHT okay I forgot about that! Thanks man!

Answer 6

YW

Answer 7

@eliassaab is my book wrong and doesnt have the right answer..?

Answer 8

Evaluate: \[\int\limits_{0}^{2}(x-6)^{3}dx\]

Answer 9

I'm getting -260 lol, and 260 and -260 arent there