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Make it single logarithmic method 1/2[logbase3(x^2-y^2)-log(x+y)]
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logbase3(x 2 - y 2) = log (x 2 -y 2) / log3 1/2 ( log (x-y)(x+y) / ( x+y) log3 ) = 1/2 ( log (x-y) / log3 )
is that over log base 3? @P0sitr0n
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