Question

Find all solutions to the given equation in the interval [0,2pi]

(sin x + 1)(tan x +1 ) = 0

Answer 1

i m writing in general form
if (x + a) (x + b) = 0
x+a = 0 or x+b = 0
hope this will help

Answer 2

So sin(x)=-1 and tan(x)=-1

Answer 3

now give the solution in radians or degrees
keeping in mind the [0,2pi]

Answer 4

That's the part I'm most confused on. It has to be in radians but how do I find it? I know it's on the unit circle but I don't remember.

Answer 5

in first quadrant ( 0< theta ≤ 90 ) all sine cosine and tangent are positive
in second quadrant ( 90< theta ≤ 180) only sine is positive
in third quadrant (180< theta ≤270) only tangent is positive
in fouth quadrant (270< theta ≤360) only cosine is positive