Algebra 2 Help :)
What is a cubic polynomial function in standard form with zeros 1 -2 and 2?
If a is a zero then (x - a) is a factor. So if 1 is a zero, then (x - 1) is a factor. You are given three zeros so you can find the three factors. Multiply them all out and arrange the polynomial from the highest degree to the lowest degree to put it in the standard form.
is it f(x)=x^3+x^2-3x+4?
not quite. try again.
you need to multiply (x-1)(x+2)(x-2) It would be easy to first multiply the last two factors because (a+b)(a-b) = a^2 - b^2
oh is it f(x)=x^3+x^2+4x+4?
as a side not: if a is a zero then (a - x) is also a suitable factor. for some reason i find it easier to remeber to subtract an x than to subtract a root
Swag. Thats dewd!
(x-1)(x+2)(x-2) (x-1)(x^2 - 4) x^3 - 4x - x^2 + 4 x^3 - x^2 - 4x + 4
OH OK! i get i now :) Thanks a lot dudes
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