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Geometry 13 Online
OpenStudy (anonymous):

geometry-attached picture..medal will be given

OpenStudy (anonymous):

OpenStudy (anonymous):

any help would be very appreciated

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (anonymous):

find the value of x and y

OpenStudy (anonymous):

are the two triangles proportional

OpenStudy (jdoe0001):

I'd think so

OpenStudy (anonymous):

ok is 3x+2y the length of the whole side or just that half?

OpenStudy (jdoe0001):

half

OpenStudy (jdoe0001):

hmmm... good point

OpenStudy (jdoe0001):

shoot I was looking for ratios and... wasn't finding much hehehe

OpenStudy (anonymous):

me too i think...like 3x-2y+8/5x-3y=8/7

OpenStudy (anonymous):

and then 3x-2y=8

OpenStudy (anonymous):

and then solve for x and make those equations equal eachother

OpenStudy (jdoe0001):

... so you'd end up with a system of equations

OpenStudy (jdoe0001):

ohh I see... substitute... right

OpenStudy (anonymous):

yeah...im just not sure if that is right

OpenStudy (anonymous):

@thomaster

OpenStudy (anonymous):

@myininaya

OpenStudy (jdoe0001):

\(\bf 3x-2y=8\implies y=\cfrac{3x}{2}-4\\ \quad \\ \cfrac{7}{5x-3y}=\cfrac{1}{2}\implies \cfrac{7}{5x-3\left(\cfrac{3x}{2}-4\right)}=\cfrac{1}{2}\\ \quad \\ 14=5x-3\left(\cfrac{3x}{2}-4\right)\implies 14=5x-\cfrac{9x}{2}+12\)

OpenStudy (jdoe0001):

if 8 is half, the other half is 8, thus 8/16 = 1/2

OpenStudy (anonymous):

i got y=2 and x=4..

OpenStudy (jdoe0001):

yeap

OpenStudy (jdoe0001):

since x = 4, you can just plug that back in \(\bf y=\cfrac{3x}{2}-4\)

OpenStudy (anonymous):

yeah thanks

OpenStudy (jdoe0001):

yw

OpenStudy (jdoe0001):

hmm y = -1 btw, after plugging it in

OpenStudy (jdoe0001):

x = 4, yes....

OpenStudy (jdoe0001):

ohh wait.... dohh.. yes is 2, nevermind =)

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