Geometry
13 Online
OpenStudy (anonymous):
geometry-attached picture..medal will be given
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OpenStudy (anonymous):
OpenStudy (anonymous):
any help would be very appreciated
OpenStudy (anonymous):
@satellite73
OpenStudy (anonymous):
@jim_thompson5910
OpenStudy (anonymous):
find the value of x and y
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OpenStudy (anonymous):
are the two triangles proportional
OpenStudy (jdoe0001):
I'd think so
OpenStudy (anonymous):
ok is 3x+2y the length of the whole side or just that half?
OpenStudy (jdoe0001):
half
OpenStudy (jdoe0001):
hmmm... good point
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OpenStudy (jdoe0001):
shoot I was looking for ratios and... wasn't finding much hehehe
OpenStudy (anonymous):
me too i think...like 3x-2y+8/5x-3y=8/7
OpenStudy (anonymous):
and then 3x-2y=8
OpenStudy (anonymous):
and then solve for x and make those equations equal eachother
OpenStudy (jdoe0001):
... so you'd end up with a system of equations
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OpenStudy (jdoe0001):
ohh I see... substitute... right
OpenStudy (anonymous):
yeah...im just not sure if that is right
OpenStudy (anonymous):
@thomaster
OpenStudy (anonymous):
@myininaya
OpenStudy (jdoe0001):
\(\bf 3x-2y=8\implies y=\cfrac{3x}{2}-4\\ \quad \\
\cfrac{7}{5x-3y}=\cfrac{1}{2}\implies \cfrac{7}{5x-3\left(\cfrac{3x}{2}-4\right)}=\cfrac{1}{2}\\ \quad \\
14=5x-3\left(\cfrac{3x}{2}-4\right)\implies 14=5x-\cfrac{9x}{2}+12\)
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OpenStudy (jdoe0001):
if 8 is half, the other half is 8, thus 8/16 = 1/2
OpenStudy (anonymous):
i got y=2 and x=4..
OpenStudy (jdoe0001):
yeap
OpenStudy (jdoe0001):
since x = 4, you can just plug that back in \(\bf y=\cfrac{3x}{2}-4\)
OpenStudy (anonymous):
yeah thanks
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OpenStudy (jdoe0001):
yw
OpenStudy (jdoe0001):
hmm y = -1 btw, after plugging it in
OpenStudy (jdoe0001):
x = 4, yes....
OpenStudy (jdoe0001):
ohh wait.... dohh.. yes is 2, nevermind =)