Question

Find the equation of the circle with center at (-4,6) and passes through point (-4,7)

Answer 1

equation of a circle in a center (h , k ) / radius r form is:
(x - h)^2 + (y - k)^2 = r^2
center: (-5 , 6)
(x + 5)^2 + (y - 6)^2 = r^2

if it passes through the point x = 1 and y = 3

(1 + 5)^2 + (3 - 6)^2 = r^2
(6)^2 + (-3)^2 = r^2
36 + 9 = r^2
r = sqrt(45)

hence the equation is:
(x + 5)^2 + (y - 6)^2 = 45

Answer 2

is that helping u???????????

Answer 3

ty