Question

rational function

Answer 1

@agent0smith wow im stuck

Answer 2

\[\frac{ c^2 - 9c + 18 }{ c^2 - 9c + 18 } - \frac{ c^2 - 6c + 9 }{ c^2 - 10c + 21}\]

Answer 3

whats the function?

Answer 4

oh ok

Answer 5

so i think you should factor the quadratics in the numerator and denominator

Answer 6

i factored them and got \[\frac{ ( c - 6 ) ( c - 3 ) }{ ( c - 6 ) ( c - 3 ) } - \frac{ ( c - 3 ) ( c - 3 ) }{ ( c - 7 ) ( c -3 ) }\]

Answer 7

so you get:
\[\frac{ (c-3)(c-6) }{ (c-3)(c-6) }-\frac{ (c-3)(c-3) }{ (c-3)(c-7) }\]

Answer 8

@agent0smith ik you told me to cancel out the common factors or whatever but how do i do that when the whole left side cancels out ?

Answer 9

@mihirb yeh basically lol

Answer 10

the left side cancels out to 1

Answer 11

so its 1 - whatever the right side equals

Answer 12

wait r u simplifying it or what are u supposed to do with it?

Answer 13

im supposed to subtract them

Answer 14

oh

Answer 15

yep

Answer 16

left side is just 1. But write it like so to make it easier\[\large \frac{ 1 }{ 1 }-\frac{ (c-3) }{ (c-7) }\]

Answer 17

thats what i said

Answer 18

ok so now find the common denominator

Answer 19

which is ( c - 7 )

Answer 20

yah so its:
\[\frac{ (c-7) }{ (c-7) }-\frac{ (c-3) }{ (c-7) }\]

Answer 21

\[\frac{ ( c - 7 ) - ( c - 3 ) }{ ( c - 7 ) }\] ??

Answer 22

not one of my answer choices though

Answer 23

simplify it first

Answer 24

^that's not right

Answer 25

I'm pretty sure @wendylisette can solve it from here. I'm sure she'll remember the negative this time ;)

Answer 26

oh i got it

Answer 27

anyway

Answer 28

a. \[\frac{ -16c + 30 }{ (c - 3 ) ( c - 7 ) }\]
b. \[\frac{ -4c + 12 }{ ( c - 3 ) ( c - 7 )}\]
c. \[\frac{ 2c^2 + 12 }{ ( c - 3 ) ( c - 7 )}\]
d. \[\frac{ 2c^2 - c + 30 }{ 2c^2 + 30 }\]

Answer 29

@agent0smith LOL yeh i remembered but my denominator still didnt match my answer choices

Answer 30

@mihirb -10

Answer 31

Are you sure this is correct \[\Large \frac{ c^2 - 9c + 18 }{ c^2 - 9c + 18 } - \frac{ c^2 - 6c + 9 }{ c^2 - 10c + 21}\]

Answer 32

@agent0smith positive

Answer 33

and what ?? lol

Answer 34

\[\large \frac{ -4c + 12 }{ ( c - 3 ) ( c - 7 )} = \frac{ -4(c -3) }{ ( c - 3 ) ( c - 7 )}\]

Answer 35

how did you get that ?

Answer 36

oh you common denominatord it

Answer 37

Factor out a -4.

No answer should be given in unsimplified form, but they did for some stupid reason. \[\large \frac{ (c-7)-(c-3) }{ (c-7) } = \frac{ -4 }{ (c-7) }\]

Answer 38

haha common denominatord it

Answer 39

so its b ?

Answer 40

No.

Answer 41

lol

Answer 42

^ LOL thats what i said

Answer 43

okay ima submit this . ill let yall know what i got

Answer 44

its:
\[\frac{ -4 }{ c-7 }\] in simplified form

Answer 45

but for your tests its b)

Answer 46

Well you got the correct answer there right? It's just not your fault that they did NOT simplify it. It's b.

Answer 47

sorry i thought u were supposed to simplify it.

Answer 48

anyway hope i helped

Answer 49

i got an 80 :( i got one wrong , help meeeee out guysss

Answer 50

You are supposed to simplify. Always. Tell your math teacher that none of theirs answers are fully simplified. Tell him you deserve extra credit for it.

Answer 51

\[\frac{ m^2 - 4m - 21 }{ m^2 - 5m - 14 } - \frac{ m^2 + 5m + 6 }{ m^2 + 2m - 3 }\]

Answer 52

Post as a new question @wendylisette

Answer 53

oh not again

Answer 54

yah new question

Answer 55

its an online class. she doesnt care about me or extra credit lol and ugh do i have to ?

Answer 56

can u write the answer choices too

Answer 57

Yes. Long questions get slow and take longer to answer.

Answer 58

This is way too long and slow already.