Question

n!/(n+1)!

Answer 1

How about explaining in words what your goal is?
(n+1) = (n+1)*n!. Can you use this fact to answer the question?

Answer 2

So if you've got a number like 10!, you know that's gonna be 10*9*8...
That's almost like saying (9+1)!. That's gonna be the same thing right? Still 10*9*8... because you know that 9+1=10.

Answer 3

Make sense so far?

Answer 4

\[\frac{4!}{5!}=\frac{1 \times 2 \times 3 \times 4}{1 \times 2 \times 3 \times 4 \times 5}=\frac{x}{5}\]See?

Answer 5

I meant 1 over 5 not x over 5, sorry.

Answer 6

Building on Pineapple's explantion: (n+1)! = (n+1)*n!.
Thus, your n!/(n+1)! reduces to n!/[(n+1)*n!].
What common factor can be cancelled here?