A rock weighs 130 N in air and has a volume
of 0.00331 m3.
What is its apparent weight when sub-
merged in water? The acceleration of gravity
is 9.8 m/s2 .
Answer in units of N

Question

A rock weighs 130 N in air and has a volume
of 0.00331 m3.
What is its apparent weight when sub-
merged in water? The acceleration of gravity
is 9.8 m/s2 .
Answer in units of N

anonymous · Answer

The buoyancy due to water offsets the rock's weight with a force equal to  the product of displaced volume times density times gravitational acceleration,
F = V rho g = (.00331m3)(1000kg/m3)(9.8N/kg)=30.4N,
so the rock will weight this much less in water, or 130N-30.4N=99.6N.

Note that g=9.8m/s2 is also g=9.8N/kg from force = mass x acceleration