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OpenStudy (anonymous):
Help finding the horizontal asymptote of (1/(x-3)^2)+1? Thanks :)
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OpenStudy (anonymous):
as \(x\) gets larger, \(\frac{1}{(x-3)^2}\) gets closer and closer to \(0\) so the whole thing gets close to \(1\) horizontal asymptote is \(y=1\)
OpenStudy (anonymous):
could you explain how you got that?
OpenStudy (anonymous):
The horizontal asymptote is the quotient of the terms of greatest exponent
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