Question

Help finding the horizontal asymptote of (1/(x-3)^2)+1?
Thanks :)

Answer 1

as \(x\) gets larger, \(\frac{1}{(x-3)^2}\) gets closer and closer to \(0\) so the whole thing gets close to \(1\)
horizontal asymptote is \(y=1\)

Answer 2

could you explain how you got that?

Answer 3

The horizontal asymptote is the quotient of the terms of greatest exponent