\[\sqrt[30]{2}\]
And the question is...
How do you solve it? Like put it in decimal form?
Can you use a calculator?
Do you know logarithm?
Yes but it doesn't give me the correct answer. And I would like to know how to solve it. I'm learning Logarithm but I don't really get it..
This is all what logarithm is: [Plus, some properties also!! :D ] If \(a^b = c\) then this can also be written as: \( \log ~~of ~~{c}~~ to~~ the ~~base ~~a~~ =~~ b\) Thus, it is another way of representing exponents. I am not quite sure, if it'll be of any use here though.
Let me just try it once.
Only for curiosity, from which lesson is this problem?
It is just a review for my final but I can't seem to remember how I'm suppose to do this. So the answer to your question is 6.7.31
Ok, I don't know how logartihms can be used to solve this problem, may be they can be useful. Another way is to use the Taylor expansion, something like this, \[\sqrt[30]{x}\approx 1+\frac{x-1}{30}-\frac{29 (x-1)^2}{1800}\] or the binomial expansion for a radical ( http://en.wikipedia.org/wiki/Binomial_theorem#Newton.27s_generalised_binomial_theorem).
But I think, the answer must not be so complicated.
I assume you know that the problem can be written as \[ 2^{\frac{1}{30}} \] if you take the log (base 10) of this you could write it as \[ \frac{1}{30} \log(2) \] if you "undo" the log by making this the exponent of 10 \[ 10^{\frac{1}{30} \log(2) } = 1.023373892 \] \[ 1.023373892^{30} = 2 \]
None of that really makes much sense, because you need a calculator to do it... so you may as well evaluate 2^(1/30) and get the answer directly.
Yes I think, this should be the best way.
Hahaa! But that was the logarithm approach!
I mean, using the calculator. :)
Well I know the answer is 1.0234.... So you would be correct!!! But what you're saying is all I had to do was 2^(1/03) and I would've gotten the right answer? That's all it is? THANK YOU ALL SO MUCH! <3
you mean 2^(1/30)
you can type 2^(1/30)= into google to see the answer
Yes I do... And Thank you so much!!!
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