Question

An archer releases an arrow from a shoulder height of 1.39 m. When
the arrow hits the target 18 m away, it hits point A. When the target is
removed, the arrow lands 45 m away. Find the maximum height of the
arrow along its parabolic path. Assume Point A is 1.28 m from the ground. (The top of the target was 1.52 m and point A is 24 cm from the top so 1.52 - .24 = 1.28 m). You now know the coordinates of 3 points on the parabolic path. You know the coordinates of the starting point and point A and the landing point. The x coordinate is the distance from the target along the ground and the y coordinate is the height above the ground. You can know find the quadratic equation through these 3 points using the graphical calculator. Once you have the equation find the maximum height

Answer 1

>.>

Answer 2

OH DANG

Answer 3

give a minute to post the picture

Answer 4

http://assets.openstudy.com/updates/attachments/508079bae4b067efc9ff1ee0-fall12-13-1350601069012-507e201be4b0919a3cf31396phi1350496607180archer.pdf TA DA

Answer 5

char i dont understand dat madness

Answer 6

LOL
Do you have choices Alley?

Answer 7

hheheheee nice drawing and no i dont have choices

Answer 8

Oh no!

Answer 9

Tell me Alley ~ What grade is this?

Answer 10

10th

Answer 11

Ah ~ So I just didn't study about it yet it seems
Lets see............

Answer 12

ur not in alg 2?

Answer 13

THAT'S WHY!
I'm taking Geometry instead xD I thought I was a potato for a second there LOL

Answer 14

ahhhhhhh char i forgot im advanced for 10th lol im on a 11th grade level

Answer 15

I'm in Honors HUE
But Advanced or not ~ I'm not taking Algebra 2 LOL
Not until next year!

Answer 16

Sorry Alley Q_Q

Answer 17

tis ok char :)