for a circle of radius 9 feet, find the arc length subtended by a central angle of 52 degrees?

A. 13pi/5
b. 11pi/5
c. 13pi/11
d. 5pi/11

Question

for a circle of radius 9 feet, find the arc length subtended by a central angle of 52 degrees?

A. 13pi/5
b. 11pi/5
c. 13pi/11
d. 5pi/11

anonymous · Answer

Arclength = $$\Theta*r$$

anonymous · Answer

how do you do that

campbell_st · Answer

well 1st you need to change 52 degrees to radians... to use the formula... 

can you don that....?

anonymous · Answer

0.91?

campbell_st · Answer

well leave it in terms of pi

$$52^o = \frac{52 \pi}{180}$$

then use the formula shown above 

$$l = r \times \theta$$

i = arc length, r = radius and theta= angle subtended... 

hope it helps

simplify the fraction answer to get an answer matches one of the choices

anonymous · Answer

how do you time it by theta though?

campbell_st · Answer

well look at it this way

$$l = 9 \times \frac{52\pi}{180}$$

cancel the common factor of 9 so

$$l = \frac{52\pi}{20} $$

just finsih cancelling common factors.

anonymous · Answer

ok i understand now thankyou