A 0.160-kg ball attached to a light cord is swung in a vertical circle of radius 70.0 cm. At the top of the swing, the speed of the ball is 3.26 m/s. The centre of the circle is 1.50 m above the floor.
Calculate the tension of the cord when the cord is 30.0° down from horizontal.

Question

homeworksucks · Answer

I drew a free-body diagram, I'm stuck on how to isolate Fg working in the same direction as the tension force

ddcamp · Answer

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homeworksucks · Answer

Ooh I see thanks so much! From then on would I use the equation $$F_{inwards}=F_t+F_g$$, right?

homeworksucks · Answer

, but I don't know the inward force..

alekos · Answer

The inward force is the force due to centripetal acceleration

this is F = ma and a = (v^2)/r,  v is the speed and r is the radius