a basketball player shoots the ball with a velocity of 17 ft/s at an angle of 35.3˚ with the horizontal. find the magnitude of the horizontal component of the result vector.

Question

anonymous · Answer

Horizontal speed = v_x = cos(theta)*v, where v is the total velocity (17 ft/s). Hence, the horizontal speed is v_x = cos(35,3 degrees)*17ft/s = 13,87 ft/s.

anonymous · Answer

Here is a good illustration. Think about x as v_x and y as v_y. https://www.google.no/search?q=dekomponering+av+hastighet&espv=210&es_sm=93&source=lnms&tbm=isch&sa=X&ei=k4GeUpieH6fiywOB3YDwCQ&ved=0CAkQ_AUoAQ&biw=1920&bih=911#facrc=_&imgdii=_&imgrc=DHkOPZOfK5W7TM%3A%3BnDaAWt1l7pQunM%3Bhttp%253A%252F%252Fwww.iu.hio.no%252F~oyvindg%252Fforelesninger_energi_miljo%252FSammendrag_av_forelesningene_2004_files%252Fimage022.jpg%3Bhttp%253A%252F%252Fwww.iu.hio.no%252F~oyvindg%252Fforelesninger_energi_miljo%252FSammendrag_av_forelesningene_2004.htm%3B566%3B374

anonymous · Answer

thanks